b^2=4.47

Solution for b^2=4.47 equation:

b^2=4.47

We move all terms to the left:

b^2-(4.47)=0

We add all the numbers together, and all the variables

b^2-4.47=0

a = 1; b = 0; c = -4.47;
Δ = b2-4ac
Δ = 02-4·1·(-4.47)
Δ = 17.88
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{17.88}}{2*1}=\frac{0-\sqrt{17.88}}{2}
=-\frac{\sqrt{}}{2}
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{17.88}}{2*1}=\frac{0+\sqrt{17.88}}{2}
=\frac{\sqrt{}}{2}
$